4L solution
Let A be the vertex.
- Construct a circle with center B on either line and radius AB. Circle B intersects with line AB at point C, and the other line at point D.
- Construct a circle with center D and radius AD. Circle D intersects with circle B at point E.
- Draw line AE, the first angle trisector.
- Bisect angle DAE, the second angle trisector.
Alternative 4L solution:
- Construct a circle with center B on either line and radius AB, intersecting the other line at point C.
- Constuct the parallel to AB through C, intersecting circle B at point D.
- Constuct line AD, the first angle trisector.
- Construct the angle bisector of ∠DAB, the second angle trisector.
5E solution
Let A be the point of intersection between the two lines
- Construct a circle with center B on either line and radius AB. Circle B intersects with line AB at point C, and the other line at point D.
- Construct a circle with center D and radius AD. Circle D intersects with circle B at point E.
- Draw line AE. This is the first angle trisector.
- Draw circle with center E and radius EC. Circle E intersects with circle B at point F.
- Draw line AF. This is the second angle trisector.
Explanation
As mentioned in the FAQ, trisection of an angle is not possible in general case, so you need to use that 54/3 = 18. You can also note that 90-54 = 36 = 2*18 and so on.