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Solutions

3L 3E Solution

Let A be the initial point of the given ray.

  1. Construct a circle C1 with center A and an arbitrary radius, intersecting the ray at B
  2. Construct the circle C2 with center B and radius AB, intersecting circle C1 at C and D
  3. Construct line AC
1.1-3L 3E.PNG

2V Solution

  1. Construct line AD
1.1-2V.PNG

Explanation

All internal angles of an equilateral triangle are 60°, so you just need to construct the two sides of an equilateral triangle adjacent to vertex A.
The two circles ensure that AB=AC=BC and AB=AD=BD and so ABC and ABD are equilateral and angles CAB and DAB are 60°.

List of Levels
Alpha Angle of 60°Perpendicular BisectorMidpointCircle in SquareRhombus in RectangleCircle CenterInscribed Square
Beta W.I.P.
Gamma W.I.P.
Delta W.I.P.
Epsilon W.I.P.
Zeta W.I.P.
Eta W.I.P.
Theta W.I.P.
Iota W.I.P.
Kappa W.I.P.
Lamda W.I.P.
Mu W.I.P.
Nu W.I.P.
Xi W.I.P.
Omicron W.I.P.
Tutorials
Equalateral Triangle • Intersect ToolPerpendicular BisectorMove ToolAngle BisectorPerpendicularParallel LineCompass
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