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3L 5E Solution

Given the rectangle ABCD.

  1. Construct the perpendicular bisector P1 of diagonal AC, intersecting AB at E and CD at F
  2. Construct line AF
  3. Construct line CE
1.5-3L 5E.PNG

2V Solution

  1. Construct the perpendicular bisector P2 of diagonal BD, intersecting AB at G and CD at H
  2. Construct line BH
  3. Construct line DG


In a rhombus, the diagonals are perpendicular bisectors to each other, so given one of the rectangle's diagonal (also one of the rhombus' diagonal), constructing its perpendicular bisector gives you the second diagonal. The intersections of that second diagonal with the rectangle give you the two remaining vertices of the rhombus.

List of Levels
Alpha Angle of 60°Perpendicular BisectorMidpointCircle in SquareRhombus in RectangleCircle CenterInscribed Square
Beta W.I.P.
Gamma W.I.P.
Delta W.I.P.
Epsilon W.I.P.
Zeta W.I.P.
Eta W.I.P.
Theta W.I.P.
Iota W.I.P.
Kappa W.I.P.
Lamda W.I.P.
Mu W.I.P.
Nu W.I.P.
Xi W.I.P.
Omicron W.I.P.
Equalateral Triangle • Intersect ToolPerpendicular BisectorMove ToolAngle BisectorPerpendicularParallel LineCompass