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Inscribed Square
Solution 6L is easy as the inscribed square's center is the same as the circle's center, so you can find the vertex opposite to A as its diametrical opposite. That diameter is also 
2.2 Intersection of Angle Bisectors
Instruction: Construct the point where the angle bisectors of the triangle are intersected. Goal: 2L 6E 
2.7 Erect a Perpendicular
Instruction: Erect a perpendicular from the point on the line. Goal: 1L 3E 
2.8 Tangent to Circle at Point
Instruction: Construct a tangent to the circle at the given point. Goal: 2L 3E 
Euclidea Wiki
Welcome to the Euclidea Wiki! We're a collaborative community website about Euclidea that anyone, including you, can build and expand. Wikis like this one depend on readers getting involved and adding content. Click the 
Circle Center
Given any two points on a circle, the perpendicular bisector of the segment made up of those two points passes through the center of the circle. Therefore, by constructing two perpendicular bisectors, you'll find 
8.4 Regular Octagon
Instruction: Construct a regular octagon with the given side. Goal: 9L 13E 2V 
Rhombus in Rectangle
In a rhombus, the diagonals are perpendicular bisectors to each other, so given one of the rectangle's diagonal (also one of the rhombus' diagonal), constructing its perpendicular bisector gives you the second diagonal. The 
Angle of 60°
All internal angles of an equilateral triangle are 60°, so you just need to construct the two sides of an equilateral triangle adjacent to vertex A. The two circles ensure that AB=AC=BC and 
Circle in Square
In a square, the center of the inscribed circle is the intersection of its diagonal and the intersection of the perpendicular bisector of its sides. Constructing one diagonal and one perpendicular bisector is enough to 
Perpendicular Bisector
Any point of a perpendicular bisector is equidistant to both A and B. The two circles ensure that AC=BC and AD=BD and so both C and D are on the perpendicular bisector of 
2.4 Double Angle
Instruction: Construct an angle equal to the given one so that they share one side. Goal: 3L 3E 
5.10 Circle Tangent to Square Side
Instruction: Construct a circle that is tangent to a side of the square and goes through the vertices of the opposite side. Goal: 3L 6E 
7.11 Excircle
Instruction: Construct the excircle of the triangle formed by the three given lines. Goal: 4L 8E 
7.3 Angle of 75°
Instruction: Construct an angle of 75° with the given side. Goal: 3L 5E 
4.10 Square by Adjacent Midpoints
Instruction: Construct a square, given two midpoints of adjacent sides. Goal: 7L 10E 
3.7 Angle of 45°
Instruction: Construct an angle of 45° with the given side. Goal: 2L 5E 
7.8 Circle Tangent to Three Lines
Instruction: Construct a circle that is tangent to the three given lines. Two of the lines are parallel. Goal: 4L 6E 
4.9 Square by Opposite Midpoints
Instruction: Construct a square, given two midpoints of opposite sides. Goal: 6L 10E 
6.11 Parallelogram by Three Midpoints
Instruction: Construct a parallelogram given three of the midpoints. Goal: 7L 10E 
3.8 Lozenge
Instruction: Construct a rhombus with the given side and an angle of 45° in a vertex. Goal: 5L 7E 
4.2 Angle of 60°  2
Instruction: Construct a straight line through the given point that makes an angle of 60° with the given line. Goal: 3L 4E 
3.6 Midpoints of Trapezoid Bases
Instruction: Construct a line passing through the midpoints of the trapezoid bases. Goal: 3L 5E 
6.10 Symmetry of Four Lines
Instruction: Three lines are intersected in a point. Construct a line so that the set of all 4 lines is mirror symmetric. Goal: 3L 4E 
5.11 Regular Hexagon
Instruction: Construct a regular hexagon with the given side. Goal: 7L 8E
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The Official Terraria Wiki is a comprehensive resource containing information about all versions of ReLogic's actionadventure sandbox game, Terraria.